What percentage of F2 generation plants from a spherical seed cross (Ss x Ss) will have dented seeds?

To determine the percentage of F2 generation plants with dented seeds from a cross where both parents have spherical seeds (Ss x Ss), we first need to understand the genetics involved.

In this scenario, S represents the allele for spherical seeds, which is dominant, while s represents the allele for dented seeds, which is recessive. Therefore, the genotypes of the plants can be categorized as follows:

• SS - homozygous dominant (spherical seeds)

• Ss - heterozygous (spherical seeds)

• ss - homozygous recessive (dented seeds)

When two heterozygous plants (Ss) are crossed, the offspring can be determined using a Punnett square. The possible combinations from this cross will be:

• SS (spherical)

• Ss (spherical)

• Ss (spherical)

• ss (dented)

Counting these combinations, we find:

• 1 SS

• 2 Ss

• 1 ss

This means there is one genotype with dented seeds (ss) out of a total of four genotypes. To find the percentage of plants with dented seeds in the F2 generation, we calculate the fraction of offspring with the dented seed genotype:

1 (