What is the genotype of a red-eyed, yellow-bodied female fruit fly who is homozygous for the eye color allele?

Explore the Mendelian Link Test. Study with questions and explanations, comprehend Mendel's principles, genetic inheritance, and related concepts. Prepare confidently for your exam!

To determine the correct genotype of the red-eyed, yellow-bodied female fruit fly, it's important to understand the genetics involved. In Drosophila melanogaster, eye color and body color are traits influenced by specific alleles on the X chromosome.

The allele for red eyes is often denoted as "w+" (wild type), while the allele for yellow eyes is "w" (mutant). Since the question specifies that the fruit fly is red-eyed, we can conclude that it must possess at least one wild type allele for eye color, symbolized as "w+", indicating that she has red eyes as a result of being homozygous for the eye color allele.

Being a female fruit fly, she has two X chromosomes. Since she is homozygous for the red-eye allele, both X chromosomes must carry the wild type allele for red eyes, which would be represented as "Xw+ Xw+". The individual also has a yellow body, typically denoted by "bw" for body color, but since the question only focuses on eye color and indicates that both alleles are the same (homozygous), the body color doesn't affect the determination of her eye color genotype.

Thus, the genotype that reflects a red

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