In a cross between a white-eyed female fruit fly and a red-eyed male, what percentage of the female offspring will exhibit white eyes?

Explore the Mendelian Link Test. Study with questions and explanations, comprehend Mendel's principles, genetic inheritance, and related concepts. Prepare confidently for your exam!

In the case of fruit flies, the trait for eye color is determined by a gene located on the X chromosome. The white-eyed trait is recessive, while the red-eyed trait is dominant. Female fruit flies have two X chromosomes (XX), while males have one X and one Y chromosome (XY).

In this scenario, the white-eyed female possesses two copies of the recessive allele for eye color (X^w X^w), whereas the red-eyed male has one X chromosome with the dominant allele (X^R Y). When these two fruit flies are crossed, all female offspring will inherit one X chromosome from each parent.

The resulting genotype for the female offspring will be X^w X^R, which means that every daughter will have one allele for the white eye trait and one allele for the red eye trait. Since the red eye trait is dominant, all female offspring will exhibit red eyes.

Thus, the percentage of female offspring exhibiting white eyes from this cross will be 0%, making that the correct answer.

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